04-28-2013, 14:24
05-17-2013, 00:18
pouzitim funkcie triu je mozne ziskat maticu ktora bude mat ostatne prvky nulove:
alebo potom naprogramovat napr:
vysledok:
pre start_x = 2;
atd...
Kód:
matica = [1 2 3; 4 5 6; 7 8 9]
matica =
1 2 3
4 5 6
7 8 9
triu(matica)
ans =
1 2 3
0 5 6
0 0 9
>> triu(matica, 1)
ans =
0 2 3
0 0 6
0 0 0
alebo potom naprogramovat napr:
Kód:
matica = [1 2 3; 4 5 6; 7 8 9];
start_x = 1;
stop_y = 1;
nad_diagonalou = [];
for i = start_x: size(matica, 2)
for j = 1 : stop_y
nad_diagonalou = [ nad_diagonalou matica(j, i) ];
end
stop_y = stop_y + 1;
end
nad_diagonalou
vysledok:
Kód:
nad_diagonalou =
1 2 5 3 6 9
pre start_x = 2;
Kód:
nad_diagonalou =
2 3 6
atd...